Built-in function_Cross analysis and instructions

Built-in function_Cross analysis and instructions

The _Cross function in the global function array in the API documentation is used to calculate the cross state of two pointer lines

• The ### function implements code similar to the following:

It's important to note thatarr1It is defined as a fast-track indicator array.arr2When defined as a slow-line indicator array,

  可知，此时```arr1```上穿```arr2```已经n个周期，此时就是快线上穿慢线代表金叉。
  同样```_Cross```函数如果返回负数，即为死叉。
  
  如果定义```arr1```为慢线指标数组，```arr2```为快线指标数组，则相反。
  ```_Cross```函数返回的值为正数代表死叉。
  ```_Cross```函数返回的值为负数代表金叉。

// Returns the number of cycles of upward wear, the positive number is the number of weeks of upward wear, the negative number is the number of weeks of downward wear, 0 is the same as the current price $.Cross = function ((arr1, arr2) { // The number of arguments is 2, as can be seen from the name of the arguments, these two arguments should be of the type of array, the array should be // as if the line segment in the coordinate system where the X axis is the index value of the array and the Y axis is the indicator value, the function is to determine the intersection of the two lines if (arr1.length!== arr2.length) { // First, we need to determine whether the two arrays are equal in length. throw array length not equal; // If unequal is thrown, the error cannot be judged for unequal pointers I'm not sure. var n = 0; // Declared variable n used to record the cross-state, initial 0, not overlapping for (var i = arr1.length-1; i >= 0; i) { // traverses the array arr1, traversing the sequence as traversed from the last element onwards if (typeof ((arr1[i])!== number typeof ((arr2[i])!== number) { // jumps out of the loop when any of the arrays of arr1 or arr2 is of non-numeric type (i.e. invalid indicator) break; // jump out of the loop I'm not sure. if (arr1[i] < arr2[i]) { // If arr1 is smaller than arr2 then n is odd, then the relative states of arr1 and arr2 are recorded at the beginning, whereas at the beginning, n is self-adjusted according to the relative sizes of arr1[i] and arr2[i], and when another relation of the opposite sizes of arr1[i] and arr2[i] occurs, the two lines intersect. If (n > 0) { I'm going to break. I'm not sure. I'm not sure. } else if (arr1[i] > arr2[i]) { // n++ if arr1 is greater than arr2 If (n < 0) { I'm going to break. I'm not sure. n++; } else { // arr1[i] == arr2[i], then jump out immediately I'm going to break. I'm not sure. I'm not sure. return n; // Returns the n-value, which represents how many cycles have been crossed, 0 is equal to the indicator value I'm not sure.

- #### 我们模拟一组数据传入该参数看看结果如何

var arr1 = [1, 2, 3, 4, 5, 6, 8, 8,9] // the fast-line indicator var arr2 = [2, 3, 4, 5, 6, 7, 7, 7] // the indicator of the slow line function main (()) { Log ((_Cross ((arr1, arr2)): the log, _Cross ((arr1, arr2)) Log ((_Cross ((arr2, arr1)): the log, _Cross ((arr2, arr1)) I'm not sure. What's up?

You can see that the result is 3, 3, 3.

As can be seen in the diagram, the position of the intersection occurs before the three K-line columns.