2.14 How to call an exchange's API
Author: Inventors quantify - small dreams, Created: 2017-05-02 11:53:48, Updated: 2017-10-11 10:23:022.14 How to call an exchange's API
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HttpQuery functions
When calling some exchange APIs that do not require authentication (e.g. API that is not related to account information), for example:
https://www.okcoin.com/api/v1/future_estimated_price.do?symbol=btc_usd // 获取交割预估价HttpQuery(“https://www.okcoin.com/api/v1/future_estimated_price.do?symbol=btc_usd”)
https://www.okcoin.com/api/v1/future_hold_amount.do?symbol=btc_usd&contract_type=next_week // 获取合约持仓量HttpQuery(“https://www.okcoin.com/api/v1/future_hold_amount.do?symbol=btc_usd&contract_type=next_week”)
The result is a string in JSON format that can be parsed as an object using the JSON.parse function.
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exchange.IOFunction
Exchange APIs that call IO functions must be authenticated (not supported by those APIs that can be accessed directly with HttpQuery).
For specific uses, see the API documentation.
- BitMEX exchange API note BitMEX exchange API terms of use
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qq47898077 因为python不支持HttpQuery，exchange.IO又必须要验证，所以我尝试用自带的urllip获取行情信息。但是Poloniex的API都有人工验证，你们是怎么解决的呢。
Inventors quantify - small dreamsI'm still learning on gihub, too: What's up? def _call ((self, mode, uri, data = None): url = '%s://%s%s' % (SCHEME, self._host, uri) # log (mode +'' + url) # print If you want to change the header, you can change the header. What do you mean? Request (url, data = data, headers = headers, method = mode) # Log (("req:", req) # print with request.urlopen ((req, timeout=TIMEOUT) as resp: If resp.getcode (()!=200: raise ApiNetworkError (('Bad response code: %s %s' % (resp.getcode(), resp.reason)) return resp.read ((() # self._parse (()) What's up? Send a request.